feat: implement recursive function przestaw and calculate results for given values
Co-authored-by: aider (openrouter/qwen/qwen3-coder) <aider@aider.chat>
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z1.c
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65
z1.c
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#include <stdio.h>
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int przestaw_calls = 0;
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int przestaw(int n) {
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przestaw_calls++;
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int r = n % 100;
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int a = r / 10;
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int b = r % 10;
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n = n / 100;
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if (n > 0) {
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return a + 10 * b + 100 * przestaw(n);
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} else {
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if (a > 0) {
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return a + 10 * b;
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} else {
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return b;
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}
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}
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}
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int main() {
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int test_values[] = {316498, 43657688, 154005710, 998877665};
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int num_tests = sizeof(test_values) / sizeof(test_values[0]);
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printf("| n | Wykonanie funkcji przestaw | Liczba wywolan funkcji przestaw |\n");
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printf("|---|---|---|\n");
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for (int i = 0; i < num_tests; i++) {
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przestaw_calls = 0;
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int result = przestaw(test_values[i]);
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printf("| %d | %d | %d |\n", test_values[i], result, przestaw_calls);
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}
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// For the very large number 998877665544321, we need to use long long
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long long large_value = 998877665544321LL;
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przestaw_calls = 0;
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// We need a modified version for long long
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long long przestaw_ll(long long n) {
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przestaw_calls++;
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long long r = n % 100;
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long long a = r / 10;
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long long b = r % 10;
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n = n / 100;
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if (n > 0) {
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return a + 10 * b + 100 * przestaw_ll(n);
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} else {
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if (a > 0) {
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return a + 10 * b;
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} else {
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return b;
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}
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}
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}
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long long large_result = przestaw_ll(large_value);
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printf("| 998877665544321 | %lld | %d |\n", large_result, przestaw_calls);
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return 0;
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}
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